.25x^2=40

Solution for .25x^2=40 equation:

.25x^2=40

We move all terms to the left:

.25x^2-(40)=0

a = .25; b = 0; c = -40;
Δ = b2-4ac
Δ = 02-4·.25·(-40)
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{10}}{2*.25}=\frac{0-2\sqrt{10}}{0.5}
=-\frac{2\sqrt{10}}{0.5}
=-\frac{\sqrt{10}}{0.25}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{10}}{2*.25}=\frac{0+2\sqrt{10}}{0.5}
=\frac{2\sqrt{10}}{0.5}
=\frac{\sqrt{10}}{0.25}
$